1 mole of Aluminium Oxide (Al2O3) = 2 × 27 + 3 × 16 = 102 g
We know, 102 g of Aluminium Oxide (Al2O3) = 6.022 × 1023 molecules of Aluminium Oxide (Al2O3)
We know, 102 g of Aluminium Oxide (Al2O3) = 6.022 × 1023 molecules of Aluminium Oxide (Al2O3)
Aluminum, also known as Aluminium, is a Block P, Group 13, Period 3 element. It is the third most abundant element in the earth's crust and the most abundant metallic element. In its elemental form, CAS 7429-90-5, Aluminum has a silvery gray metallic appearance. ››Al2O3 molecular weight. Molar mass of Al2O3 = 101.961276 g/mol This compound is also known as Aluminium Oxide. Convert grams Al2O3 to moles or moles Al2O3 to grams. Molecular weight calculation: 26.981538.2 + 15.9994.3.
We know, The number of atoms present in given mass = (Given mass ÷ molar mass) × Avogadro number
= (0.051 ÷102 ) × 6.022 × 1023 molecules of Aluminium Oxide (Al2O3)
= 3.011 × 1020 molecules of Aluminium Oxide (Al2O3)
The number of Aluminium ions (Al3+) present in one molecule of aluminium oxide is 2.
Therefore, the number of Aluminium ions (Al3+) present in 3.011 × 1020 molecules (0.051 g ) of Aluminium Oxide (Al2O3)
= 6.022 × 1020
This is an answered question from Chapter 3. Atoms And Molecules of CBSE Class 9th Science
Mass Of Aluminum
Check for Complete Exercise Solution for Chapter 3. Atoms And Molecules | CBSE Class 9th Science